Welcome to the website of ME 274 for the Fall 2008 semester. On this site you can view blog posts, add your own blog posts and add comments to existing posts. In addition to the blog are links to course material: course information, information on solution videos, exams, quizzes, homeworks and other course-related material. Direct links to the homework solution videos are also available on the left side of this page.


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Dec 4, 2008

About the Exam 3 Solution

Professor, I noticed on the solution for the first problem on the exam that there was no force due to gravity shown acting on the bar in the Free Body Diagram. Is there supposed to be? I am unclear as to why there wouldn't be one somewhere on there. The way it's shown, it looks like the only force acting in the y direction is the Normal force at A pushing the bar upward, which I assume would imply that it's being lifted off the ground.

3 comments:

Sam Morford said...

I think that system was in the horizontal plane, so there wouldn't be any force from gravity shown when "looking down" on the system.

CMK said...

Sam is correct -- motion in the horizontal plane means that the gravitational force does not influence the motion since that force acts perpendicular to the plane of motion.

You are correct -- the normal force at A (NA) is the only force acting in the y-direction. Because of this, NA creates the y-component of acceleration aGy. NA results from the constraint that A must move in only the x-direction. However, NA does NOT cause the bar to lift off the surface; it simply keeps it there.

Let us know if this does not answer your question.

Anonymous said...

OK, thanks. I must not have read it correctly.