
Here are some suggestions in solving this problem:
- Attach observer to the disk. Let xyz be attached to the disk. Let XYZ be a fixed set of axes. (Note that in the above figure I have changed the names of these axes from that given in the text to make these names more consistent with what we have used in lecture.)
- Note that the above choice of observer sets the omega vector used in the kinematics equations to be that of the disk. Also note that omega_x is about the FIXED axis X, whereas omega_z is about the MOVING axis z.
- When you differentiate the omega vector to find the alpha vector recall that X is fixed and z is moving.
- For this choice of observer, both the velocity and acceleration of B as seen by the observer on the disk is ZERO.
- When using the velocity equation, v_B = v_O + (v_B/O)_rel + omega x r_B/O, note that O is an acceptable point to use since O is attached to the same rigid body as the observer (do you see this?). O is a good point to choose since it has both zero velocity and zero acceleration.
- Repeat the above for the acceleration of point B.
Let us know if you have any questions.
2 comments:
how would i find the relative velocity?
Since the observer and point B are both on the disk, the relative velocity term (v_B/O)_rel is zero. Same thing for the relative acceleration term.
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