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Jul 16, 2008

Problem 6 /115



My answer is a little bit off so i am trying to figure out what i am doing wrong. I set my datum at the bars initial position.
U = 0
V1=0
V2= -(m*g*(L\4) + 2*m*g*(3L/4))
T1 = 0
T2 = .5*Io*w^2
Io = 1/12 *m * L^2 + m*(L/4)^2 + 2*m*(3L/4)^2
the 2*m*(3L/4)^2 was to try and add in the IMM of the particle and that is where i think i might be wrong.

4 comments:

tjmackey said...
This comment has been removed by the author.
tjmackey said...

Your equation for I_0 looks correct I had the same one.

I_0 = 61/48 ml^2

I think your error is in the V2 equation…both terms should be negative.

kceisel said...

They are both negative. They in inside the parenthesis.

kceisel said...

I made an algebra error. nevermind. It is right.