Welcome to the website of ME 274 for the Fall 2008 semester. On this site you can view blog posts, add your own blog posts and add comments to existing posts. In addition to the blog are links to course material: course information, information on solution videos, exams, quizzes, homeworks and other course-related material. Direct links to the homework solution videos are also available on the left side of this page.


The following is a reverse chronological order listing of the posts for the course blog. To add a post, click here (when adding posts, be sure to add a "label" in the box at the lower right side of the post window). To add a comment to an existing post, click on the "Comments" link below the post.


____________________________________________________

Nov 12, 2008

Homework Problem No. 6/152

Suggestions:
  1. FBD
  2. Work-Energy
  3. Kinematics
  4. Solve
This problem is very similar to the example problem on page 71 of the lecture notes that was worked out in class. Use that problem as a guide (particularly for the kinematics that caused your instructor problems during lecture...). In particular, use the result discussed in lecture that omega_AB = -omega_OB.

Let us know if you have any questions.



5 comments:

Sheng Yang said...

Just as an FYI for anyone else who didn't know this, the work done by a couple is integral(M dtheta). It is on page 471.

Adam Watson said...

so for this problem, would the work be M*theta or 2*M*theta. I was figuring it would be the former since it is acting on the one member which only changes a single value of theta, but I wasn't sure since the same moment is also causing the movement of the other arm theta degrees as well.

Lindsey VanDeMark said...

I am with you, I think it is just M*theta because if you look at the diagram they have separated the theta into two for you already, so they are taking the mirrored movement into account that way. Just my thoughts, hope they help.

rpmccaul said...

but it acts on AB from A to O which would be 2 theta, right? Since we are interested in A as it strikes O?

John Boguski said...

I think omega_AB causes bar AB to only rotate theta, and omega_OB causes bar OB to rotate theta as well, giving a total of 2(theta). Since M is applied to bar AB, I think it should only cover an angle of theta.