Welcome to the website of ME 274 for the Fall 2008 semester. On this site you can view blog posts, add your own blog posts and add comments to existing posts. In addition to the blog are links to course material: course information, information on solution videos, exams, quizzes, homeworks and other course-related material. Direct links to the homework solution videos are also available on the left side of this page.


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Apr 5, 2008

Problem 6/203

How would I go about finding the mass moment of inertia for the arms of this guy? First I tried using a uniform bar on top of the cylinder, only to realize that the bars are two seperate ones that start on the edge of the cylinder. The only guess I have is that the R used in the 1/12mR^2 equation would be the radius of the cylinder and the bar combined, but I don't believe that will work. Help please....
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1 comment:

Steve Musick said...

You’ll need to use the Parallel Axis Theorem to get the moment of inertia. In this case that would be 1/12 * m * L^2 + m * D^2, where L is the length of each arm and D is the distance from the center of gravity for each arm to the center of the cylinder.

April 5, 2008 at 8:16 PM

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